$a(x)=x^2+x+1$, and $b(x)=x-1$. We can rewrite $\dfrac{a(x)}{b(x)}$ as $q(x) + \dfrac{r(x)}{b(x)}$ where $q$ and $r$ are polynomials and the degree of $r$ is less than the degree of $b$. **What is the quotient, $q(x)$**? $ q(x)=$ [[☃ expression 1]] **What is the remainder, $r(x)$**? $r(x)=$ [[☃ expression 2]]