Consider the table with function values for $f(x)=\dfrac{\cos2x-\cos3x}{x^2}$ at $x$-values near zero. $\qquad x$|$f(x)$ -:|:- $-0.1$|$2.473009$ $-0.01$|$2.499729$ $-0.001$|$2.499997$ $0.001$|$2.499997$ $0.01$|$2.499729$ $0.1$|$2.473009$| **From the table, what does** $\qquad \displaystyle \lim_{x\to 0}\dfrac{\cos2x-\cos3x}{x^2}$ **appear to be?** The limit appears to be [[☃ math-keypad 1]]