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Derivative applications challenge

An active volcanic mountain grows in the shape of a cone while maintaining its base diameter equal to its height. The height of the mountain increases at a rate of 22 feet per year.
At what rate is the volume of the mountain increasing when the height is 3,0003{,}000 feet?
Express your answer to the nearest tenth (i.e. 0.1 ~0.1~) of a cubic foot per year.
[Note: The volume of a cone is π3r2h\dfrac{\pi}{3}r^2h, where rr is the radius of the base and hh is the height of the cone.]
feet3year\dfrac{\text{feet}^3}{\text{year}}