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Extraneous solutions of radical equations

Divya is solving the following equation for ww.
3w205w=23w-\sqrt{20-5w}=2
Her first few steps are given below.
3w=205w+23w2=205w(3w2)2=(205w)29w212w+4=205w\begin{aligned} 3w&=\sqrt{20-5w}+2\\ \\ 3w-2&=\sqrt{20-5w}\\ \\ (3w-2)^2&=\left(\sqrt{20-5w}\right)^2\\ \\ 9w^2-12w+4&=20-5w \end{aligned}
Is it necessary for Divya to check her answers for extraneous solutions?
Choose 1 answer:
Choose 1 answer: