Two stoves were turned off at the same time, and they both started to cool down. The temperature of the first stove (in degrees Celsius) as a function of time (in minutes) is given by the following function: $\qquad T(t) = 180-1.55t$ The graph of the temperature of the second stove (in degrees Celsius) as a function of time (in minutes) is shown below. **Which stove started at a higher temperature?** [[☃ radio 1]] **Which stove cooled down at a greater rate?** [[☃ radio 2]]