Consider the table with function values for $f(t)=\dfrac{t^8-1}{t^5-1}$ at $t$-values near $1$. There are two values missing in the table. Use a calculator to evaluate $f(t)$ at $t=0.99999$ and $t=1.00001$, and enter these numbers in the table rounded to the nearest $0.000001$. **From the table, what does** $\qquad \displaystyle \lim_{t\to 1}\dfrac{t^8-1}{t^5-1}$ **appear to be?** $t$|$f(t)$ -:|:- $0.999$|$1.597603$ $0.9999$|$1.599760$ $0.99999$|[[☃ input-number 1]] $1.00001$|[[☃ input-number 2]] $1.0001$|$1.600240$ $1.001$|$1.602403$| The limit appears to be [[☃ input-number 3]]