Gabe wants to find the derivative of $g(x)=-\dfrac{2}{x}$ at the point $x=1$. His table below shows the slopes of the secant lines to the graph of $g$ between the points $(1,g(1))$ and $(x,g(x))$ for $x$-values that get increasingly closer to $1$: $x$|Slope of secant line, $\dfrac{g(x)-g(1)}{x-1}$ :- | :- | :- $0.9$| $2.2222$ $0.99$| $2.0202$ $0.999$| $2.0020$ $1.001$| $1.9980$ $1.01$| $1.9802$ $1.1$| $1.8182$ **From the table, what does the derivative of $g(x)=-\dfrac{2}{x}$ at $x=1$ appear to be?** [[☃ math-keypad 1]]