Olivia wants to find the derivative of $g(x)=-5e^x$ at the point $x=0$. Her table below shows the average rate of change of $g$ over the intervals $[x,0]$ or $[0,x]$ for $x$-values that get increasingly closer to $0$: $x$|Interval|Average rate of change, $\dfrac{g(x)-g(0)}{x-0}$ :- | :- | :- $-0.1$|$[-0.1,0]$|$-4.7581$ $-0.01$|$[-0.01,0]$|$-4.9751$ $-0.001$|$[-0.001,0]$|$-4.9975$ $0.001$|$[0,0.001]$|$-5.0025$ $0.01$|$[0,0.01]$|$-5.0251$ $0.1$|$[0,0.1]$|$-5.2585$ **From the table, what does the derivative of $g(x)=-5e^x$ at $x=0$ appear to be?** [[☃ input-number 1]]