Consider the table with function values for $f(t)=\dfrac{1+t^2}{1-t^2}$ at $t$-values near $1$. $t$|$f(t)$ -:|:- $0.9$|$9.52632$ $0.99$|$99.50251$ $0.999$|$999.50025$ $1.001$|$-1000.50025$ $1.01$|$-100.50249$ $1.1$|$-10.52381$| **From the table, what does** $\qquad \displaystyle \lim_{t\to 1}\,\dfrac{1+t^2}{1-t^2}$ **appear to be?** [[☃ radio 1]]