Wilson tried to evaluate an expression step by step.
$\qquad\begin{align}
&\Large\dfrac{ ~\frac{3}{-2}~ }{ \frac{9}{-4}} \\\\
\\
=&\dfrac{9}{-4}\div \dfrac{3}{-2}&\green{\text{Step } 1}\\\\
\\
=&\dfrac{9}{-4}\cdot \dfrac{-2}{3}&\blue{\text{Step } 2}\\\\
\\
=&\:\:\:\dfrac{3}{2}&\purple{\text{Step } 3} \\\\
\end{align}$
**Find Wilson's mistake.**
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