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Divide polynomials with remainders

Let a(x)=6x3+19x2+8x+12a(x)=-6x^3+19x^2+8x+12, and b(x)=3x2+x+1b(x)=3x^2+x+1.
When dividing aa by bb, we can find the unique quotient polynomial qq and remainder polynomial rr that satisfy the following equation:
a(x)b(x)=q(x)+r(x)b(x)\dfrac{a(x)}{b(x)}=q(x) + \dfrac{r(x)}{b(x)},
where the degree of r(x)r(x) is less than the degree of b(x)b(x).
What is the quotient, q(x)q(x)?
q(x)= q(x)=
What is the remainder, r(x)r(x)?
r(x)=r(x)=