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Solve square-root equations (basic)

Solve the following equation for zz.
z2+6z+3=3z+1\sqrt{z^2+6z+3}=3z+1
z=z =
  • Your answer should be
  • an integer, like 66
  • a simplified proper fraction, like 3/53/5
  • a simplified improper fraction, like 7/47/4
  • a mixed number, like 1 3/41\ 3/4
  • an exact decimal, like 0.750.75
  • a multiple of pi, like 12 pi12\ \text{pi} or 2/3 pi2/3\ \text{pi}