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The volume of a cylinder is increasing at a rate of 10π10\pi cubic meters per hour.
The height of the cylinder is fixed at 55 meters.
At a certain instant, the volume is 80π80\pi cubic meters.
What is the rate of change of the surface area of the cylinder at that instant (in square meters per hour)?
Choose 1 answer:
Choose 1 answer:
The surface area of a cylinder with base radius rr and height hh is 2πr2+2πrh2\pi r^2+2\pi r h.
The volume of a cylinder with base radius rr and height hh is πr2h\pi r^2h.