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Direct comparison test

We know that
0<2n3n(n+7)<(23)n0<\dfrac{2^n}{3^n(n+7)} < \left(\dfrac{2}{3}\right)^n
for any n1n\ge 1.
Considering this fact, what does the direct comparison test say about n=12n3n(n+7)\displaystyle\sum\limits_{n=1}^{\infty }\dfrac{2^n}{3^n(n+7)} ?
Choose 1 answer:
Choose 1 answer: